Question

Factroise the following:-
12x²y² - 300

I need step by step explaination.

Please those who know the method and answer only they answer the question..spammers get lost from here.​

Answer 1

Answer:

12(xy+5)(xy-5)

Step-by-step explanation:

Well first you can take 12 common from here and then the expression becomes 12(x^2Y^2-25)

therefore, 12((xy)^2-5^2)

Now using the formula a^2-b^2=(a+b)(a-b), it becomes:

12(xy+5)(xy-5)

Hope it helps... :)

Answer 2

AnswEr

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We're provided with the expression we need to Factorise that expression :

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• 12x²y² - 300.

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We'll factorize this equation to use the polynomial formula of sum and difference.

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$\sf{:\implies 12x^2 y^2 - 300}$

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Bind the expression with the common factor 12,

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$\sf{:\implies 12(x^2 y^2 - 25)}$

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Binding the power,

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$\sf{:\implies 12\big\lgroup(xy)^2 - 25 \big\rgroup}$

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Present as the shape of the power,

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$\sf{:\implies 12\big\lgroup(xy)^2 - 5^2 \big\rgroup}$

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Organize by using A² - = (A + B)(A - B),

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$\sf{:\implies 12(xy + 5) (xy-5)}$

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Sort the factor,

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$\sf{:\implies \boxed{\textsf{\textbf{12(xy - 5) (xy + 5)}}}}$

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∴ The factorization of 12x²y² - 300 is 12(xy - 5) (xy + 5).