Question

factroize the 3x²+6x+3​

Answer 1

$\huge\mathfrak{\color{orange}{\underline {\underline{Answer♡}}}}$

${3x}^{2} + 6x + 3$

Factor out 3 from the expression.

$3( {x}^{2} + 2x + 1)$

$\rm\red {Using\: Identity}$

$\rm\red {{(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} }$

$3(x + 1) {}^{2}$

Answer 2

$3x^{2} +6x+3=0$

We can Split the Middle Term of this expression to factorise it.  

In this technique, if we have to factorise an expression like  $ax^{2} +bx+c$ , we need to think of 2 numbers such that:

$N1.N2=a.c=3.3=9$

and  

$N1+N2=b=6$

After trying out a few numbers we get  $N1=3$ and  $N2=3$  

$3.3=9$ , and  $3+3=6$

$3x^{2} +6x+3=3x^{2} +3x+3x+3$

$=3x(x+1)+3(x+1)$

$(3x+3)(x+1)$  is the factorised form.

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