Question

fair die is thrown once. The probability of getting a composite number is

(a) 1/3 (b) 1/6 (c) 2/3 (d) 0​

Answer 1

Step-by-step explanation:

let S be the sample space of throwing a doe

S={1,2,3,4,5,6}

n(S)=6

let A be the event of getting a composite number

={4,6}

n(A)=2

$= \frac{n(a)}{n(s)} \\ = \frac{2}{6} \\ = \frac{1}{ 3}$

Answer 2

Answer:

Option (a) is correct

Probability (of getting a composite number) = (1/3)

Step-by-step explanation:

When a dice is thrown,

Total Possible outcomes = {1, 2, 3, 4, 5, 6}

So,

Number of total possible outcomes = 6

Prime numbers are numbers that have only 2 factors, 1 and the number itself.

And composite number are numbers that have more than 2 factors.

Here,

1 is neither prime nor composite

2 is prime

3 is prime

4 is composite

5 is prime

6 is composite

Thus,

Out of the possible outcomes,

Favourable outcomes of Composite numbers = {4, 6}

So,

Number of Favourable outcomes = 2

Now,

Probability (of getting a composite number) = (Number of Favourable outcomes)/(Number of Total Possible outcomes)

P (of getting a composite number) = (2/6)

P (of getting a composite number) = (1/3)

Hence,

Option (a) is correct

Probability (of getting a composite number) = (1/3)

Hope it helped you and believing you understood it...All the best