Question

Fair spinner a has four equal sections labelled 1,2,3,4. Fair sided spinner b has four equal sections labelled 2,3,4,5. Both spinners are sun and added up. Work out the probability that the number is 5 or less. Give answer in fraction

Answer 1

Given:

Two fair sided spinners.

Spinner A has four equal sections 1, 2, 3 and 4.

Spinner B has four equal sections 2, 3, 4 and 5.

The two spinners are spun and added up.

To find:

The probability that the number is 5 or less.

Solution:

Total number of cases when the two spinner are spun:

4 $\times$ 4 = 16

Favorable cases when the sum is 5 or less =

{(1, 2), (1, 3), (1, 4)

(2, 2), (2, 3)

(3, 2)}

So, only above 6 cases are favorable as per the given condition that the sum is 5 or less.

Formula for probability of an event E is given as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}\\\Rightarrow P(Sum\le 5) = \dfrac{6}{16}\\\Rightarrow P(Sum\le 5) = \bold{\dfrac{3}{8}}$

So, the answer is:

$\bold{\dfrac{3}{8}}$

Answer 2

Answer:

2/8

Step-by-step explanation: