faktor dari 2x²-9x-35
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Answered by
17
Step-by-step explanation:
Given quadratic equation
2x²-9x-35
2x² - 14x + 5x - 35 = 0
[because -14x × 5x = -35 × 2x² and -14x + 5x = -9x]
2x² - 14x + 5x - 35 = 0
2x(x - 7) +5(x - 7) = 0
(2x + 5)(x - 7) = 0
now,
2x + 5 = 0
2x = -5
x = -5/2
and also,
x - 7 = 0
x = 7
so,
factors of 2x² - 9x - 35
are 2x + 5 and x - 7
and its zeros are -5/2 and 7
it means that
when We put either -5/2 or 7 at the place of x then it will give 0
for example
2x² - 9x - 35 = 0
putting 7 at the place of x
2x² - 9x - 35 = 0
2(7)² - 9(7) - 35
98 - 63 - 35
98 - 98
= 0
so, factors = 2x + 5 and x - 7
zeros = -5/2 and 7
hope it helps u
Answered by
3
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