Question

Family of
Find the equation of the line through the point (1, 2), whose distance from the point
(3,1) is under root 5​

Answer 1

Answer:

Step-by-step explanation:

Let the equation of the line be  

y=mx+c

Since it passes through (1,2), therefore

2=m+c

Or  

c=2−m

Therefore  

y=mx+2−m.

Its distance from (3,1) is  

=∣  

1+m  

2

 

​  

 

3m+2−m−1

​  

∣

s=∣  

1+m  

2

 

​  

 

2m+1

​  

∣

dm

ds

​  

=  

1+m  

2

 

2  

1+m  

2

 

​  

−  

2  

1+m  

2

 

​  

 

2(m)2m+1

​  

 

​  

=0

Or  

1+m  

2

 

​  

=  

2  

1+m  

2

 

​  

 

m(2m+1)

​  

 

2(1+m  

2

)=2m  

2

+m

2+2m  

2

=2m  

2

+m

m=2

Hence, equation of the line is  

y=2x+(2−2)

y=2x.

Answer 2

Step-by-step explanation:

y=2x is the answer Tq so much