Question

Family use a light bulb of 100w a fan of 100w ang a heater of 1000w each for 8 hours a day if the cost of electricity is rs 2 per unit what is the expenditure for the family per day on electricity

Answer 1

Usage of Electric bulb = 100W

Usage of Electric fan = 100W

Usage of Electric heater = 1000W

Total Power usage = 100 + 100 + 1000 = 1200W

Total Power usage in kW $=\frac{1200}{1000}$

$=1.2 kW$

Total time = 8 hours

Therefore, total Energy used $= kW \times hours$

$=1.2 \times 8$

$=9.6$

Rate per kWh = ₹2

Therefore, total cost for one day $= Rate \times kWh$

$= 2 \times 9.6$

$= 19.2$

The electricity bill for one day is ₹19.2.

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Answer 2

Explanation:

Usage of Electric bulb = 100W

Usage of Electric fan = 100W

Usage of Electric heater = 1000W

Total Power usage = 100 + 100 + 1000 = 1200W

Total Power usage in kW =\frac{1200}{1000}=

1000

1200

=1.2 kW=1.2kW

Total time = 8 hours

Therefore, total Energy used = kW \times hours=kW×hours

=1.2 \times 8=1.2×8

=9.6=9.6

Rate per kWh = ₹2

Therefore, total cost for one day = Rate \times kWh=Rate×kWh

= 2 \times 9.6=2×9.6

= 19.2=19.2

The electricity bill for one day is ₹19.2.