Far point of a person is 5 m. What is the lens he should use to correct his defect? What is it's focal length ?
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Answer:
x− distance of far point =5meters
f=focal length of correcting lens
For lens, v=image distance=−x ,u=object distance =α
f
1
=
v
1
+
u
1
=
−x
1
+
α
1
So f=−5m
Since it is negative ,it is concave lens.
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