Question

far point of myopic eye is 90cm. power of lens required to correct the defect is

Answer 1

Answer:

The nature of the lens used to correct myopic eye is a convex lens.

The power to be used is given by Power of lens, P = 1/f

Far point is 90 cm

u = - infinity and v = -90 cm

Using Lens formula

1/f = 1/v - 1/u

1/f = 1/-90 - 1/-infinity

f = -90 cm

P = 1/f = -1/90*10^-2

= -1.11 D

Power of the lens is -1.11 D

Answer 2

Answer:

P=1/f

F=90cm=0.9m

P=1/(-0.9)

P= -1.11D

Where D stands for diopter

Explanation:

Hope this helps