Math, asked by navramgarhia63, 9 months ago

Fare of a Taxi costs ₹ 30 for the first km and increase by 12 for each additional km. What will be the charge after traveling of 50km. ​

Answers

Answered by avitaylor101
13

Step-by-step explanation:

The charge after travelling of 50 km =

{ Rs 30 + ( 12 × 49)}

= Rs { 30 + 588}

= Rs 618 answer

Answered by PoojaBurra
1

Given:

Fare of taxi for first km = ₹ 30

Increase in taxi fare for each aditional km = ₹ 12

To find:

The chare after travelling for 50 km

Calculation:

The fare for the taxi increases by 12 Rs for each addition km and the fare for the first km is 30 Rs. This can be solved by relating the data to arithmetic progression

First term(a) = 30

Common difference(d) = 12

Number of terms(n) = 50

Charge after travelling 50 km = n/2[2a+(n-1)d]

                                                  = (50/2)[2(30) + (50-1)12]

                                                  = 25(60+588)

                                                  = 25(648)

                                                  = 16,200

The charge after travelling for 50 km is Rs 16,200

Similar questions