Question

Farhan has three pieces of rope with lengths of 140 cm, 160 cm and 210 he wishes to cut all the three pieces of ropes into smaller pieces of equal length such that there is no leftover rope (i) what is the greatest possible length of each of the smaller pieces of rope (ii) how many smaller pieces of rope can he get all together​

Answer 1

Answer:

For finding this, we need to find the HCF of 140 cm 168 cm and 210 cm.

So, HCF(168, 210)

210 = 168 × 1 + 42

168 = 42 × 4 + 0

HCF(168, 210) = 42

HCF(42, 140)

140 = 42 × 3 + 14

42 = 14 × 3 + 0

HCF(42, 140) = 14

Now the length of the pieces will be 14cm

168 \div 14 = 12168÷14=12

210 \div 14 = 15210÷14=15

140 \div 14 = 10140÷14=10

Hence the number of pieces he will get is = 12 + 15 + 10 = 37.