Question

Farhan has three pieces of rope with lengths of 140 cm, 168 cm and 210 cm. he wishes to cut all the three pieces of ropes into smaller pieces of equal length such that there is no leftover rope. How many smaller pieces of rope can he get altogether?

Answer 1

For finding this, we need to find the HCF of 140 cm 168 cm and 210 cm.
So, HCF(168, 210)
210 = 168 × 1 + 42
168 = 42 × 4 + 0
HCF(168, 210) = 42

HCF(42, 140)
140 = 42 × 3 + 14
42 = 14 × 3 + 0
HCF(42, 140) = 14

Now the length of the pieces will be 14cm
$168 \div 14 = 12$
$210 \div 14 = 15$
$140 \div 14 = 10$

Hence the number of pieces he will get is = 12 + 15 + 10 = 37.

Answer 2

Answer:

Step-by-step explanation:

first we will take the hcf of 140, 168 and 210

hcf: 14

divide the hcf with all the lengths:

140/14 = 10

168/14 = 12

210/14 = 15

10+12+15 = 37