Farhan, Nora, and Devi are given 3 rods of equal lengths. Farhan cuts his rod
into smaller pieces of equal length of 42 cm; Nora cuts her rod into smaller
pieces of equal length of 24 cm and Devi cuts her rod into smaller pieces of
equal length of 60 cm. If there are no rods leftover, what is the shortest
possible length of rod given to each of them?.
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Answers
Answered by
3
Answer:
20, 35 and 14
Step-by-step explanation:
LCM of 42, 24 and 63 = 2×2×2×3×5×7
= 840.
Farhan's rod = 840/42 = 20
Nora's rod = 840/24 = 35
Devi's rod = 840/60 = 14.
Answered by
3
Answer:
840cm
EXPLAINATION:
Lendth of rods : 42cm, 24cm, 60cm
to find the lowest possible length of the rod we need to find a number which is divisible by 42, 24 and 60 which is its LCM
Prime factorization of:
42 = 2×3×7
24 = 2×2×2×3
60 = 2×2×3×5
therefore the LCM = 2×2×2×3×7×5 = 840
therefore ANSWER = 840cm
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