Question

Farheen is twice as old as Sadaf. five years ago her age was three times sadaf's age find their present ages​

Answer 1

let ,present age of Sadaf=x years

present age of Farheen=2x years

5 years ago,

Sadaf's age=(x-5)years

Farheen's age=(2x-5)

also 5 years ago Farheen's age was three times Sadaf's age

i. e.

2x-5=3(x-5)

2x-5=3x-15

-5+15=3x-2x

x=10

Therefore, present age of Sadaf =x=10 years

present age of Farheen=2x=2×10=20 years

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