Farmer jones sold a pair of cows for rs. 210 , on one he made a profit of ten percent and on the other he lost ten percent. Altogether he made a profit of five percent. How many did each cow originally cost him?
Answers
Answer:
One cow cost Rs 150 and the other cost Rs 50
Step-by-step explanation:
Selling Price of 2 cows = Rs 210
Find the total cost price of the two cows:
Profit = 5%
Selling Price = Cost Price + Profit
Selling Price = 100 + 5 = 105%
105% = Rs 210
1% = 210 ÷ 105 = Rs 2
100% = 2 x 100 = Rs 200
Define x:
Let the cost of one of the cow be Rs x
The other cow is Rs (200 - x)
He made a profit of 10% on one of them
Profit =10% of x = 0.1x
Selling Price = x + 0.1x = 1.1x
He made a lost of 10%
Loss = 10% of (200 - x)
Loss = 0.1(200 - x) = 20 - 0.1x
Selling Price = (200 - x) - (20 - 0.1x)
Selling Price = 200 - x - 20 + 0.1x
Selling Price = 180 - 0.9x
Solve x:
Total selling price = Rs 210
1.1x + 180 - 0.9x = 210
0.2x = 30
x = 150
Find the cost of the cow:
one cow = x = Rs 150
other cow = 200 - x = 200 - 150 = 50
Answer: One cow cost Rs 150 and the other cost Rs 50
Answer: 50 , 150
Step-by-step explanation:
Total 5 % profit on Rs. 210
So the original price = Rs 200
Lets assume one cow price = Rs.x
So another cow price = Rs. (200 - x)
Now loss of 10 % on X = 10 x / 100
& profit of 10 % on ( 200 - x ) = (200 - x ) 10 /100
x - ( 10 x / 100 ) + (200 -x ) + ( 200 - x) 10 /200 = 210
By solving this x =Rs. 50
So one cow is of X = Rs. 50
other cow is 200-x = 200 - 50
=Rs. 150