farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial.
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Side = 10m
Time = 40s
Total Time = 2 minute 20 second =140s
Displacement = 10m x 140s / 40s = 10m x 3.5 = 35m
Time = 40s
Total Time = 2 minute 20 second =140s
Displacement = 10m x 140s / 40s = 10m x 3.5 = 35m
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time taken to cover 1 side = 40 second
time given = 140 second
displacement = 140/40=3.5
displacement = 10 × 3.5=35 m
time given = 140 second
displacement = 140/40=3.5
displacement = 10 × 3.5=35 m
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