Question

FARMER TOM’S CHICKENS AND SHEEP ARE ALL IN A JUMBLE. HE COUNTS 48 HEADS AND 134 LEGS, HOW MANY SHEEP DOES HE HAVE?

Answer 1

Let the number of chickens be x,
and the number of sheeps be y

One chicken has ;
1 head & 2 legs

One sheep had ;
1 head & 4 legs

x+y = 48
x = 48-y

2x+4y = 134
x+2y = 67
x = 67-2y

48-y = 67-2y
2y-y = 67-48
y = 19

x = 48-y
x = 48-19
x = 29
______________
Hence Tom have 19 sheeps.

Answer 2

Solution:-

Let the sheep be 's'
and the chicken be 'c'
Each has only 1 head.
So, According to the question.
s + c = 48 ..............(1)
And each sheep has 4 legs and each chicken has 2 legs.
So, 
4s + 2c = 134 ............(2)

Now,
Multiplying (1) by 2, we get.
2s + 2c = 96 ...............(3)
Now, subtracting (3) from (2)

    4s + 2c = 134
    2s + 2c =  96
  -      -         -
______________
    2s         = 38
______________

s = 19
So the farmer has 19 sheep.
Answer.