Question

Farooq purchases two watermelons, one weighing 20% more
than the other. However, due to the summer heat, the combined
weight of the two watermelons reduced by one-fourth. Of the
weight of the heavier watermelon reduces to 75% of its initial
weight, then the lighter watermelon incurs a weight loss of

Answer 1

Let a watermelon weigh x gm
and therefore by ATQ,another will weigh x+x×20%=6x/5=1.2x gm

Due to summer heat the combined weight of the two watermelons reduced by one-fourth
So, initial weight of the two watermelons=2.2x gm and final weight of the watermelons =2.2x/4 gm

Also given that the heavier watermelon loses its weight by 75%
Therefore reduced weight of the second watermelon=1.2x-1.2x×3/4=0.3x gm

Therefore the reduced weight of the first watermelon=2.2x/4-0.3x=x/4 gm

Reduced percentage of weight of the 1st watermelon ={(x-x/4)/x}×100=75%

Therefore the 1st watermelon incurs a weight loss of 75%

Hope it is correct and helps you the best...