Farsighted woman has a near point of 1.5 m. calculate the focal length of the lenses for her
eye glasses so that she can read a book held at 25 cm. also find power of the lens.
1) f = + 20 cm and p = + 4.4 d 2) f = + 10 cm and p = + 5.4 d
3) f = + 30 cm and p = + 3.3 d 4) f = + 10 cm and p = + 2.3 d
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Answer:
c) f=+30 p=+3.3
Explanation:
u=-25 cm
v=-1.5 m (near-point of women)
= -150 cm
1/f= 1/v - 1/u = 1/-150 + 1/25 = 5/150
f=+30cm
p=1/f(in meters) = 1/0.3 = 3.33 d
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