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Let the two adjacent angles be x° and 2x° .
In a parallelogram, the sum of adjacent angles is 180°.
∴ x + 2x = 180°
⇒ 3x = 180°
⇒ x = 60°
Thus , the two adjacent angles are 120° and 60°. Hence, the angles of the parallelogram are 120°, 60°, 120° and 60°.
In a parallelogram, the sum of adjacent angles is 180°.
∴ x + 2x = 180°
⇒ 3x = 180°
⇒ x = 60°
Thus , the two adjacent angles are 120° and 60°. Hence, the angles of the parallelogram are 120°, 60°, 120° and 60°.
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Let ABCD be the Parallelogram.
Let angle A be x°.
So, angle B(adjacent angle of angle A) will be 2x
or, ∠B=2x .....(i)
We know that the adjacent angles of a parallelogram form a linear pair of angles(i.e. their sum is 180°)
∴ According to question:
⇒ 2x+x=180
⇒3x= 180
⇒x= 180/2 ⇒ ∠A= 60°
Now, Putting value of x in (i):
2x ⇒ 2×60° ⇒ ∠B=120°
Since opposite angles of a parallelogram are equal,
∴ ∠A=∠C= 60°
and, ∠B=∠D= 120°
Hope this helps.
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