FAST ANSWER QUESTIONS
7.solve 4x²-4a²x+(a^4-b^4) = 0
hint the answer contains a and b
Answers
Answered by
1
A. 4x²-4a²x+(a⁴-b⁴)=0
4x²-2(a²-b²)x-2(a²+b²)x+(a⁴-b⁴)=0
2x[2x-(a²-b²)]-(a²+b²)[2x-(a²-b²)]=0
[2x-(a²+b²)][2x-(a²-b²)]=0
2x-(a²+b²)=0 or 2x-(a²-b²)=0
x=(a²+b²)/2 or x=(a²-b²)/2
4x²-2(a²-b²)x-2(a²+b²)x+(a⁴-b⁴)=0
2x[2x-(a²-b²)]-(a²+b²)[2x-(a²-b²)]=0
[2x-(a²+b²)][2x-(a²-b²)]=0
2x-(a²+b²)=0 or 2x-(a²-b²)=0
x=(a²+b²)/2 or x=(a²-b²)/2
MichalBay:
I hope it is helpful for you..
CORRECT ANSWER NOW TRY FAST ANSWER LEVEL 2
where is that?
Similar questions