Question

fast
class 10
chapter 8or 9
no spam

Answer 1

(√3+1)(3-Cot30°)=tan³60°-2sin60°

=>(√3+1)(3-√3)=(√3)³-2*(√3/2) [Cot30°=√3, tan60°=√3, sin60°=√3/2]

=>3√3-3+3-√3=3√3-√3

=>2√3=2√3

LHS=RHS