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class 10
chapter 8or 9
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(√3+1)(3-Cot30°)=tan³60°-2sin60°
=>(√3+1)(3-√3)=(√3)³-2*(√3/2) [Cot30°=√3, tan60°=√3, sin60°=√3/2]
=>3√3-3+3-√3=3√3-√3
=>2√3=2√3
LHS=RHS
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