fast
class 10
chapter 8or 9
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q=sec+cosec
p=sin+cos
solution,
q(p²-1)=2p
sec+cosec[(sin+cos)²-(sin²+cos²)=2(sin+cos) [1=sin²+cos²]
sec+cosec[(sin²+cos²+2sin.cos-sin²-cos²)]=2(sin+cos)
sec+cosec(2sin.cos)=2(sin+cos)
sec(2sin.cos)+cosec(2sin.cos)=2(sin+cos)
(1/cos)(2sin.cos)+(1/sin)(2sin.cos)=2(sin+cos)
2sin+2cos=2(sin+cos)
2(sin+cos)=2(sin+cos)
LHS=RHS
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