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A ball is thrown vertically upwards from the ground. It crosses a point at height of 60 m twice at an interval of 4 s. The velocity with which ball will hit the ground is 40 m/s 20 m/s 30 m/s 15 m/s
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Explanation:
At the point 25m above it takes 4 sec. i.e., time of flight there is 4 s.
4=
g
2u
u=20m/s
at 25m height it has velocity 20m/s and it goes further height of
2g
u
2
=20m
Total max height =20+25=45m
Initial velocity.
45=
2g
u
2
u=30m/s
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