Question

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Answer 1

Answer:

$\: by \: remaindertheoram \\ \: x + 1 = 0 \\ x = 0 - 1 \\ x = - 1 \\p(x) = (x {}^{31} + 31) \\ p( - 1) = ( - 1) {}^{31 +} + 31 \\ - 1 + 31 = 30 \\ so \: remainder \: can \: be \: 30$

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Answer 2

Answer:

BY USING REMAINDER THEOREM

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