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There are two charges 10mC at A (0, 0) and -25C at B (8m, 0). Find the force on a charge 2mC at C (4m, 3m). Express your answer as a vector.
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Answers
Answer:The Position vector of two point (1,1,−1) and (2,3,1)
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3m
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3mq1=q2=1nC=10−9C
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3mq1=q2=1nC=10−9CThe magnitude of electric force is given by
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3mq1=q2=1nC=10−9CThe magnitude of electric force is given byF=4πε01.r2q1q2
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3mq1=q2=1nC=10−9CThe magnitude of electric force is given byF=4πε01.r2q1q2F=9×109×(3)210−9×10−9
The Position vector of two point (1,1,−1) and (2,3,1) r=(2−1)i^+(3−1)j^+(1+1)k^r=i^+2j^+2k^r=∣r∣=(1)2+(2)2+(2)2=3mq1=q2=1nC=10−9CThe magnitude of electric force is given byF=4πε01.r2q1q2F=9×109×(3)210−9×10−9F=9×10−9×
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