Question

Fast im postin 2 more questions after this also

Answer 1

Explanation:

Given u=90km/h=90*5/18=25m/s a=-0.5m/s^2

t=v-u/a

t=(0-25)/0.5

t=50s

distance travelled by train before stopping

s=25(50)-1/2 (0.5)(50)^2

s=1250-625

s=625m