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Find the unknown marked angles......
Answers
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Answer:
iii.}
x° = 135°
iv.}
x° = 110°
y° = 40°
Step-by-step explanation:
iii.}
We have,
As BC = AB, angle A = angle C. {Tri. ABC becomes isosceles triangle.}
As angle B = 90°.
Let Angle A = Angle C = y.
Now, according to Angle sum property,
Angle A + Angle B + Angle C = 180°
y + 90° + y = 180°
2y = 180° - 90°
y = 90°/2
y = 45°
So, Angle A = Angle C = 45°
Now,
x° = Angle C + Angle B. {Ex. angle property}
x° = 45° + 90°
x° = 135°
iv}
We have,
As AC = AB, Angle ABC = Angle ACB. {Tri. ABC becomes isosceles triangle.}
Now,
Angle ABC = 180° - Angle EBC
Angle ABC = 180° - 110°
Angle ABC = 70°
So, angle ABC = angle ACB = 70°.
x° = 180° - angle ACB
x° = 180° - 110°
x° = 70°
Now,
y° = Angle x° - Angle ABC. {Ex. angle property.}
y° = 110° - 70°
y° = 40°
{Hope it helped you...}
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