Question

fast!! plzz need to do other problems also​

Answer 1

Answer:

Explanation:

by using conservation of energy but also taking frictional force into account

length of the inclined plane 10m by using sin 30

frictional force =u×N            (n=normal force)

f=0.2×mgcos30

f=3.464 n

work done by frictional force =3.464×10=34.64

total energy at the top of the inclined plane =100 joule   (w=mgh)

energy converted to kinetic energy=100-34.64=65.36 joule

1/2mv²=65.36

since m=2 kg

v²=65.36

v=8.08 m/s