Math, asked by neetutomer, 1 year ago

fast send the answer​

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Answered by MʏSᴛᴇʀɪᴏSᴛᴀʀᴋ
0

answer:

6

step-by-step explanation:

kx^2-13x+6=0

substitute x value

k (3/2)^2-13 (3/2)+6=0

9k/4-39/2+6=0

lcm is 4

9k-78+24/4=0

by cross multiplication 0×4=0

9k-78+24=0

9k-54=0

transfer 54

9k=54

transfer 9

k=54/9

k=6

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