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answer:
6
step-by-step explanation:
kx^2-13x+6=0
substitute x value
k (3/2)^2-13 (3/2)+6=0
9k/4-39/2+6=0
lcm is 4
9k-78+24/4=0
by cross multiplication 0×4=0
9k-78+24=0
9k-54=0
transfer 54
9k=54
transfer 9
k=54/9
k=6
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