Question

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Answer 1

Answer:

Here's your answer:

Step-by-step explanation:

In ΔADN and ΔCBP

AND = CPB (90°)

AD = CB (Opp. sides of a parallelogram)

ADN = CBP (Interior alternate angles)

∴ By, AAS ΔADN ≅ ΔCBP

∴AN = CP (∵ ADN ≅ CBP)

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Answer 2

Step-by-step explanation:

in triangle ADN&triangle CBP

AD=CB(opposite side of parallelogram)

angle AND=angle CPB(90')

angle ADN=angle PBC(AB//BC,BD is transvaal)

(alternate interior angle)

1)therefore triangle ADN =triangle CBP(ASA rule)

2)AN=CP(by CPCT)

( prove)