Question

fast tell answer only. not explain me only answer.... ​

Answer 1

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR=AS=

2

6

=3 cm

OR=OS=OM=5 m [radii of circle]

In △OAR

OA

2

+AR

2

=OR

2

OA

2

+3

2

=5

2

OA=

25−9

OA=4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS=90

o

RC=CM

Area of △ORS=

2

1

×OA×RS

2

1

×RC×OS=

2

1

×4×6

RC×5=24

RC=4.8 m

RM=2RC=2×4.8=9.6 m

So, distance between Reshma and Mandip is 9.6 m

i hope it will help you...