Question

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Answer 1

Answer:

Curved surface area of cone will be painted=πrl

h=1m;radius=240=20cm=0.2m

and let l be the slant height,

∴l2=h2+r2=12+0.22

⇒l=1+0.04=1.04=1.02m  (∵1.04=1.02 is given in the question)

⇒Curved surface area of 1 cone=πrl=(3.14×0.2×1.02)m2=0.64046m2

⇒ Curved surface area of 50 cones=50×0.64046=32.028m2

Cost of painting 1m2=Rs.12

∴ Cost of painting 32.028m2=(12×32.028)=384.336m2≈384.34

∴ Cost of painting 50 cones is Rs.384.84

Explanation:

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Answer 2

Explanation:

Curved surface area of cone will be painted=πrl

h=1m;radius=240=20cm=0.2m

and let l be the slant height,

∴l2=h2+r2=12+0.22

⇒l=1+0.04=1.04=1.02m  (∵1.04=1.02 is given in the question)

⇒Curved surface area of 1 cone=πrl=(3.14×0.2×1.02)m2=0.64046m2

⇒ Curved surface area of 50 cones=50×0.64046=32.028m2

Cost of painting 1m2=Rs.12

∴ Cost of painting 32.028m2=(12×32.028)=384.336m2≈384.34

∴ Cost of painting 50 cones is Rs.384.84

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