Question

Fastest Is the Brainliest

Answer 1

Given :-

(x + y) = 4

Solution:-

$\: \: \: \: \: \: \: \: {(x + y)}^{3} = {(4)}^{3} \\ = > {x}^{3} + {y}^{3} + 3xy(x + y) = 64 \\ => {x}^{3} + {y}^{3} +12xy = 64 \\ = > {x}^{3} + {y}^{3} - 64 + 12xy = 0$

Answer 2

Answer:

0

Step-by-step explanation:

x^3 + y^3 + 12xy - 64

= x^3 + y^3 + 3(4xy) - 4^3

= (x + y - 4)(x^2 + y^2 + 4^2 - xy - 4y - 4x) -----(1)

We know x + y = 4 -----(2)

Substituting x + y = 4 in first equation we get

(4 - 4)(x^2 + y^2 + 4^2 - xy - 4y - 4x)

= (0)(x^2 + y^2 + 4^2 - xy - 4y - 4x)

= 0

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