Math, asked by Aashi567, 8 months ago

Fastly give the answer.

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Answered by Anonymous
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Answer:

let the equation be dx^4 + ax^2 + bx + c = 0

Let the zeroes of the equation be,

alpha=2, beta=1, gamma=4

We know that,

alpha+beta+gamma= -a/d

alpha*beta*gamma= -c/a

(alpha*beta)+(beta*gamma)+(gamma*alpha)= b/d

(here the situation is changing as the equation is slightly different)

On comparing the above results, a=-7, b=14, c=-8 and d=1

HOPE U UNDERSTOOD.......

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