Question

fastorize X^2 - 1/9​

Answer 1

${x}^{2} - { (\frac{1}{3} )}^{2}$

using,

${a}^{2} - {b}^{2} = (a + b)(a - b)$

here,

$(x + \frac{1}{3} )(x - \frac{1}{3} )$

Answer 2

Answer:

${x}^{2} - \frac{1}{9} = {x}^{2} - {( \frac{1}{3}) }^{2} = (x + \frac{1}{3} )(x - \frac{1}{3} )$

IDENTITY USED:

a^2 - b^2 = (a + b)(a - b)

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