Question

fastttt
.
.its urgent
.
Plzzz solve q no. 47
.in rough note book...

Answer 1

☆Hey friend!!! ☆

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HERE IS YOUR ANSWER ☞
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${( \frac{ {x}^{p} }{ {x}^{q} }) }^{p + q} \times ( { \frac{ {x}^{q} }{ {x}^{r} } )}^{q + r} \times ( { \frac{ {x}^{r} }{ {x}^{p} }) }^{r + p} \\ \\ = > {x}^{(p - q)(p + q)} \times {x}^{(q - r)(q + r)} \times {x}^{(r - p)(r + p)} \\ \\ = > {x}^{( {p}^{2} - {q}^{2} ) } \times {x}^{ ({q}^{2} - {r}^{2} )} \times {x}^{( {r}^{2} - {p}^{2}) } \\ \\ = > {x}^{( {p}^{2} - {q}^{2} + {q}^{2} - {r}^{2} + {r}^{2} - {p}^{2} )} \\ \\ = > {x}^{0} \\ \\ = > 1 \: \: \: \:...... answer$

WE KNOW THAT :-
$= > {(something)}^{0} \: is \: always \: = 1$

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Hope it will help you ☺☺
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