Question

fasttttttttttttt answer​

Answer 1

★GIVEN★

Sides of a triangle are:

1. $\large{\sf{{x}^{2}+20}}$
2. $\large{\sf{2{x}^{2}+6x+7}}$
3. $\large{\sf{5{x}^{2}-4x+15}}$

★To Find★

Perimeter of the triangle.

★SOLUTION★

We know that perimeter of a triangle is the sum of all its sides.

So,

According to the question,

$\large\implies{\sf{({x}^{2}+20)+(2{x}^{2}+6x+7)+(5{x}^{2}-4x+15)}}$

$\large\implies{\sf{{x}^{2}+20+2{x}^{2}+6x+7+5{x}^{2}-4x+15}}$

$\large\implies{\sf{{x}^{2}+2{x}^{2}+5{x}^{2}+6x-4x+20+7+15}}$

$\large\therefore\boxed{\bf{8{x}^{2}+2x+42}}$

$\large{\purple{\underline{\boxed{\therefore{\bf{Perimeter=8{x}^{2}+2x+42}}}}}}$