Question

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Answer 1

Answer:

class interval frequency c.f. (comulative frequency)

20-40 7 7

40-60 15 7+15=22 =cf

60-80 20=f 22+20=42

80-100 8 42+8=50

n= 50

Median class interval = 60-80

L (lowest class interval) = 60,

f = 20, C.f. = 22, h (difference of the class interval) = 20

n ÷ 2 = 50 ÷ 2 = 25.

Median = l +{ ( n÷2 - cf ) ÷ f } × h

= 60 + { (25 - 22) ÷ 20 } × 20

= 60 + { (3 ÷ 20) } × 20

= 60 + ( 0.15 ) × 20

= 60 + 3

= 63

Step-by-step explanation:

The median of the statement is 63

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Answer 2

Median is the middle

Therefore it is a number in between 60-80