Math, asked by sumakadlimatti60724, 7 months ago

father age is four times his son's present Age 4 years ago father was six times as old as his son find the present age of son​

Answers

Answered by TheProphet
7

S O L U T I O N :

Let the present age of son's be r years & the present age of father's be 4r years .

\underbrace{\bf{4\:years\:ago\::}}

The age of the son's was = (r-4) years .

The age of the father's was = (4r-4) years .

A/q

\mapsto\tt{(4r-4) = 6(r-4)}

\mapsto\tt{4r-4= 6r-24}

\mapsto\tt{4r-6r= -24+4}

\mapsto\tt{-2r= -20}

\mapsto\tt{r= \cancel{-20/-2}}

\mapsto\bf{r=10\:years}

Thus;

The present age of son's r = 10 years .

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