Question

father age is four times his son's present age four years ago, father was six times as old as his son find the present age of ​

Answer 1

Answer:

10 and 40 years

Step-by-step explanation:

 Let the present age of son be 'a'. So present age of father = 4 times of a = 4a.

   Four years ago:

       Age of father = 4a - 4

       Age of son = a - 4

In question, 4 year ago:

 ⇒ age of father = 6 * age of son

 ⇒ 4a - 4 = 6(a - 4)

 ⇒ 4a - 4 = 6a - 24

 ⇒ 24 - 4 = 6a - 4a

 ⇒ 20 = 2a

 ⇒ 10 = a

          Hence,

Present age of son = 10 year

                        father = 4*10 = 40

Answer 2

Answer:

Present age of son= 10 years

Present age of father= 40 years

Step-by-step explanation:

present age of son be 'x'

present age of father will be '4x'

4 years ago son was 'x-4'

4 years ago father was '4x-4'

ATQ

4x-4 = 6(x-4)

or, 4x-4 = 6x-24

or, -4+24=6x-4x

or, 20 = 2x

∴x=10

Present age of son= x = 10 years

Present age of father= 4x = 4*10 = 40 years

      HOPE IT HELPS YOU