Father age is three times as old as his son 15 year hence he will be twice as old as his son what is the sum of his present age
Answers
Answer:
age of father = X
We need to set up an equation for his unknown age. Let us denote his unknown age by X. Let us denote his son’s age by y. Both x and y are they current ages. So we express the fact xis 3 times y
x=3y Next we add 15 years to their current ages. and we know the father will only be twice as old as son. Writing it as an equation we have
x+15= 2(y+15) =2y+30 Let us subtract the upper equation from this one
15= 2y-3y +30 or 15=30-y Let us rearrange to have y on one side and the constant terms on the other side
15–30=-y or -15=-y, means y=15. So the son is 15 years old now.
We get the father’s current age from the top equation x=3y =3*15+45
Let us see if our answer is right. !5 years later the father will be 45+15=60 years old. The son will be 15+15+ 30 years old. Indeed the father will be twice as old as the son.
Answer:
Let his son's age be x
A.T.Q.
Father's age = 3x
15 years hence,
Father's age = (3x +15)
His son's age = (x +15)
A.T.Q.
(3x +15) = 2(x +15)
3x + 15 = 2x + 30
x = 15
His son's age = 15 years
Father's age = 3x15 = 45 years