father age is three times the sum of the ages of two children after 5 years his age will be twice the sum of the ages of two children find the present age of the father
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Let the present sum of the sons’ ages be X years. Then, the father’s present age is 3X years.
5 years later, sum of the sons’ ages = X+2∗5X+2∗5years = (X+10)(X+10) years, and the father’s age would be (3X+5)(3X+5) years.
According to given, 3X+5=2(X+10)=>X=15.3X+5=2(X+10)=>X=15.
Thus, the father’s present age is (3 x 15) years = 45 years.
5 years later, sum of the sons’ ages = X+2∗5X+2∗5years = (X+10)(X+10) years, and the father’s age would be (3X+5)(3X+5) years.
According to given, 3X+5=2(X+10)=>X=15.3X+5=2(X+10)=>X=15.
Thus, the father’s present age is (3 x 15) years = 45 years.
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