Father and son completes task together in 15 days .work done by father in 1 day is equal to 3 times the work done by son find number of days required alone by the father and son
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x+y=15
y=x/3
x+x/3=15
4x/3=15
4x=15*3
4x=45
x=45/4
y=x/3
x+x/3=15
4x/3=15
4x=15*3
4x=45
x=45/4
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