Question

Father and son decide to sum their age .their sum is equal to 60 . six years ago the age of father was five times the age of son. Six years from now the son's age will be?

Answer 1

Step-by-step explanation:

let father's age be x and son's age is y

x+y=60

x-6=5y solving both equations we get y=9 x=51

six years from now the son's age will be 9+6=15yrs

Answer 2

Answer:

$\huge\rm{Let,}$

Father = F

Son = S

$\huge\rm{Solution}$

[tex]\rm→ F+S=60 \\ \\\rm→ F-6 =(S-6)5 \\ \rm→F-6=5S-30 \\ \rm→F-5S=-24 \\ \rm→F+S=60 \\ \rm→F-5S=-24 \\ \rm→6S=84 \\ \rm→S=14 \\ \rm→14+6=20[tex]

Sons age = 14

Father's age = 20