Question

father bought a cake tess ate 3/5 and anna ate 2/10 how much of the cake did tess eat more than that
1. 6/25
2.2/10
3.2/5
4.3/6​

Answer 1

Answer:

3rd options

Step-by-step explanation:

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Answer 2

Answer:

$\large\boxed{\rm{ \underline{Option \: (3) \: \dfrac{2}{5}}}} \: \checkmark$

Step-by-step explanation:

Given :

• Father bought a cake, tess ate 3/5 and anna ate 2/10.

To Find :

• How much of cake did tess eat more than that.

Elucidation :

In this question, we are provided that a father bought a cake and Tess ate $\sf \dfrac{3}{5}$ of the cake & on the other hand Anna ate $\sf \dfrac{2}{10}$ of the cake. And here we are asked to calculate how much did tess ate more than anna.

To solve this question, simply we need to apply the subtraction method. We'll subtract 2/10 from 3/5 and will find the final result. [answer]

Calculation :

Substituting values,

$\longrightarrow \sf\dfrac{3}{5} - \dfrac{2}{10}$

Here, we need to make the denominator of 3/5 same as 2/10

By multiplying 3 × 2/5 × 2 [Performing multiplication],

$\longrightarrow \sf\dfrac{3 \times 2}{5 \times 2} - \dfrac{2}{10}$

Performing subtraction,

$\longrightarrow \sf\dfrac{6}{10} - \dfrac{2}{10}$

Arranging the terms,

$\longrightarrow \sf\dfrac{6 - 2}{10}$

By subtracting,

$\longrightarrow \sf\dfrac{4}{10}$

Now, calculating in simplest form, for this we'll be applying division method. [By dividing 4 & 10 with 2]

$\longrightarrow \sf\dfrac{4 ÷ 2}{10 ÷ 2}$

By dividing,

$\longrightarrow { \boxed{\bf\dfrac{2}{5}}} \ \purple{ \bigstar}$

Therefore, 2/5 of cake was eaten by tess more than Anna.