Math, asked by shivadharshansa, 9 months ago

Father has left to his children several identical gold coins. According to his will, the oldest child receives
one coin and one-seventh of the remaining coins, the next child receives two coins and one-seventh of the
remaining coins, the third child receives three coins and one seventh of the remaining coins, and so on
through the youngest child. Every children inherits an integer number of coins. If the total number of coins
is m and the number of children is n, then find the value of (m - n).​

Answers

Answered by amitnrw
2

Answer:

m - n = 30

Step-by-step explanation:

As Every child get 6/7 of some ineteger coins

=> nth Child will Get  multiple of 6 Coins

Let say

n = 6

Coin before 5th child  = 6 * 7/6  + (5) =  12

Coin before 4th child  = 12 * 7/6  + (4) =  18

Coin before 3rd child  = 18 * 7/6  + (3) =  24

Coin before 2nd child  = 24 * 7/6  + (2) =  30

Coin before 1st  child  = 30 * 7/6  + (1) =  36

m = 36

m - n  = 30

Similar questions