Math, asked by glakticks, 1 month ago

father is 10 times as old as his son. After 6 years the father will be 4 times the age of his son. Find the present ages of father and son.

Answers

Answered by anshu123saxena
0

Step-by-step explanation:

Let the age of son be x

Let the age of son be xSo, father's age be 6x

Let the age of son be xSo, father's age be 6xsecond condition

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 year

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 yearhence,

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 yearhence,son's age is 6 year

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 yearhence,son's age is 6 yearfather's age is 36 year.

Let the age of son be xSo, father's age be 6xsecond condition=4(x+4)=6x+4x=6 yearhence,son's age is 6 yearfather's age is 36 year. Mark me as a brainliest answer.

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