Math, asked by wwwswastimamagar, 2 months ago

father is 20 years oder than her daughter. five years ago, he was
three times as old as his son was. Find their present age​

Answers

Answered by BrainlyRaaz
15

Solution :

Let the daughter age be x

The father age be (20 - x) years

5 year's ago :

Daughter age = x - 5 years

Father age = 20 - x - 5 years

Father age = 15 - x years

Now,

= 15 -x = 3(x - 5)

= 15 - x = 3x - 15

= -x - 3x = -15 - 15

= -4x = -30

= x = -30/-4

= x = 7.5 years ans.

Answered by mrmajnu51
2

Step-by-step explanation:

ANSWER ✍️

_____________

Let the daughter age be x

The father age be (20 - x) years

5 year's ago

Daughter age = x - 5 years

Father age = 20 - x - 5 years

Father age = 15 - x years

So now,

  • = 15 -x = 3(x - 5)

  • = 15 - x = 3x - 15

  • = -x - 3x = -15 - 15

  • = -4x = -30

  • = x = -30/-4

  • = x = 7.5 years ans.

hope this helps you

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