Math, asked by rajbhanushali, 1 year ago

- Father is 3 times more aged than his daughter. If after 5 years, he would be 3 times of
daughter's age, then further after 5 years, how many times he would be of his daughters
age?
a. 1 (72) times b. 2 times
c. 2.5 times
d. 3 times
e. None of these​

Answers

Answered by mpurandhar24
0

Answer:

Step-by-step explanation:

Let daughters age be x

Father's age =3x+x=>4x

After 5 years

Daughters age=x+5

Father's age =3x+15

4x+5=3x+15

=>X=10

After another 5 years

Daughters age=x+10=>20

Father's age=>3x+15+5

3×10+20=50

=>2.5 times

Answered by Dhruv4886
0

Given:

Father is 3 times more aged than his daughter. If after 5 years, he would be 3 times of  daughter's age, then further after 5 years,

To Find:

how many times he would be of his daughters  age?

a. 1 (72) times

b. 2 times

c. 2.5 times

d. 3 times

e. None of these​

Solution:

Let the age of the daughter be x, then the age of the father would be,

=x+3x

=4x(fathers age)

After 5 years the ages now will be,

daughter= x+5

father= 4x+5

and it is also said that now after 5 years the father's age is 3 times the age of his daughter, from this we can equate that,

3(x+5)=4x+5

3x+15=4x+5

x=10

So the current age of them are

daughter=x+5

              =15

father=4x+5

         =45

So their age after 5 more years will be

daughter=20

father=50

which is 50/20=2.5 times the age of his daughter.

Hence, the correct option is (c).

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